10x^2+76x-192=0

Solution for 10x^2+76x-192=0 equation:

10x^2+76x-192=0

a = 10; b = 76; c = -192;
Δ = b2-4ac
Δ = 762-4·10·(-192)
Δ = 13456
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{13456}=116$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(76)-116}{2*10}=\frac{-192}{20}
=-9+3/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(76)+116}{2*10}=\frac{40}{20}
=2
$